# Quiz with answers — Kimi Delta Attention: a bounded case study

### Question 1

Solve the worked-case variant: Increase the second gate channel from [0.9,0.2] to [0.9,0.24]. Compare the trace retained in that channel after one step with all other values fixed.

- A. For an initial trace of 1, the second channel retains 0.24 instead of 0.20, which is 20% more. The first channel stays at 0.9, so the vector gate changes memory channel by channel.
- B. For vector gate [0.9,0.2], the first channel retains almost all its trace while the second forgets quickly. The same delta correction can therefore have different temporal effects by channel.
- C. Exact Kimi K3 specifications are not claimed as verified in this lesson; the vendor technical report (Kimi Linear, arXiv:2510.26692, to verify) is cited without independent replication.
- D. Replace the scalar with a vector: a = [0.9, 0.2], S′ = diag(a)·S. Channel 1 retains — half-life ln(0.5)/ln(0.9) ≈ 6.6 tokens — while channel 2 flushes (≈ 0.43): a 15× ratio inside the same state.

**Answer: A.** For an initial trace of 1, the second channel retains 0.24 instead of 0.20, which is 20% more. The first channel stays at 0.9, so the vector gate changes memory channel by channel. The correct answer executes the requested change and gives a checkable result; the other texts do not close this calculation or trace.

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### Question 2

Which causal order correctly connects the first three stages of “Kimi Delta Attention: a bounded case study”?

- A. Delta correction → Per-channel decay → Established mechanism
- B. Established mechanism → Per-channel decay → Delta correction
- C. Per-channel decay → Established mechanism → Delta correction
- D. Established mechanism → Delta correction → Per-channel decay

**Answer: B.** Established mechanism → Per-channel decay → Delta correction The chain follows the taught progression; reversing stages consumes a representation or state before it is produced.

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### Question 3

If “Delta correction” is removed, which diagnostic method is defensible?

- A. Also change the data to amplify the difference.
- B. Observe only the final output and invent the cause.
- C. Keep the same input, predict the first output that depends on “Delta correction,” then compare the before/after trace.
- D. Conclude that the whole system fails before measuring.

**Answer: C.** Keep the same input, predict the first output that depends on “Delta correction,” then compare the before/after trace. One intervention and a prior prediction make the delta attributable to the removed mechanism.

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### Question 4

Which verdict respects this session’s validity boundary?

- A. The mechanism guarantees accuracy, speed, and stability for every workload.
- B. One successful example proves the whole architecture is superior.
- C. The mechanism name alone is enough for a production choice.
- D. Exact Kimi K3 specifications are not claimed as verified in this lesson; the vendor technical report (Kimi Linear, arXiv:2510.26692, to verify) is cited without independent replication.

**Answer: D.** Exact Kimi K3 specifications are not claimed as verified in this lesson; the vendor technical report (Kimi Linear, arXiv:2510.26692, to verify) is cited without independent replication. The correct answer bounds the conclusion; the others turn a local relation into a global guarantee.

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### Question 5

Which evidence best matches the stated status of “Kimi Delta Attention: a bounded case study”?

- A. Mixed: established mechanisms + source-reported Kimi K3-style choices.
- B. The route loads without an error.
- C. Every learner opened the file.
- D. The same result is assumed on every hardware target.

**Answer: A.** Mixed: established mechanisms + source-reported Kimi K3-style choices. Product or mechanism evidence must remain attributed and measured; availability and completion do not prove value.

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### Question 6

When should a simpler baseline be preferred to “Source-reported”?

- A. Never: the newest mechanism wins by default.
- B. When a controlled test shows equivalent quality with lower memory, latency, or complexity.
- C. As soon as one memory metric falls, regardless of quality.
- D. As soon as the diagram contains fewer components.

**Answer: B.** When a controlled test shows equivalent quality with lower memory, latency, or complexity. The choice depends on a measured trade-off on the real workload, not novelty or one isolated metric.

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### Question 7

A learner gets the right result but cannot explain “Per-channel decay.” Which remediation is most useful?

- A. Accept the answer because the final number is correct.
- B. Provide the final result a second time.
- C. Rebuild the first missing transformation, label its inputs and outputs, then test a neighboring case.
- D. Change several variables and ask for an intuition.

**Answer: C.** Rebuild the first missing transformation, label its inputs and outputs, then test a neighboring case. The remediation targets the first causal break and then requires transfer instead of rewarding a guessed result.

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### Question 8

Which submission actually demonstrates the outcome “Classify claims by evidence strength.”?

- A. A list of terms without causal relations.
- B. A screenshot without values or interpretation.
- C. A confident claim without a baseline or threshold.
- D. A trace with starting data, transformations, observed result, boundary, and next experiment.

**Answer: D.** A trace with starting data, transformations, observed result, boundary, and next experiment. The correct submission makes the reasoning reproducible and the verdict revisable by future measurement.
